How do you simplify #(- 3\sqrt { 7} + 2\sqrt { 2} ) ^ { 2} #?

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Answer 1 · 2018-05-16T20:00:22

#(-3sqrt7+2sqrt2)^2=#
#(2sqrt2-3sqrt7)^2=#
#((2sqrt2)^2-2*(2sqrt2)(3sqrt7)+(3sqrt7)^2)=#
#(4*2-2*6sqrt14+9*7)=#
#8-12sqrt14+63=#
#71-12sqrt14#