How do you simplify #(-3-sqrt2)/(3sqrt17)#?

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Answer 1 · 2018-05-21T17:38:49

#(-9sqrt17-3sqrt(34))/(153)#

#(-3-sqrt2)/(3sqrt17)#

you rationalize the denominator using:

#(3sqrt17)/(3sqrt17) = 1#

#(-3-sqrt2)/(3sqrt17)*(3sqrt17)/(3sqrt17)#

#(-9sqrt17-3sqrt(34))/(3^2*(sqrt17)^2)#

#(-9sqrt17-3sqrt(34))/(9*17)#

#(-9sqrt17-3sqrt(34))/(153)#