How do you simplify #3/(sqrt7-sqrt2)#?

1 Answer
Jul 19, 2018

Answer:

#3/5(sqrt7+sqrt2)#

Explanation:

By rationalising the denominator which means that you multiply by the conjugate of your denominator

ie the denominator is #sqrt7-sqrt2# so the conjugate of the denominator is #sqrt7+sqrt2#

#3/(sqrt7-sqrt2)#

=#3/(sqrt7-sqrt2)times(sqrt7+sqrt2)/(sqrt7+sqrt2)#

=#(3(sqrt7+sqrt2))/(7-2)#

=#3/5(sqrt7+sqrt2)#