# How do you simplify (30-i)-(18+6i)+30i and write the complex number in standard form?

Apr 1, 2017

$12 + 23 i$

#### Explanation:

$\left(30 - i\right) - \left(18 + 6 i\right) + 30 i$

expand brackets:

$30 - i - 18 - 6 i + 30 i$

collect like terms:

$30 - i - 18 - 6 i + 30 i = 12 + 23 i$

standard form: $a + b i$
hence, $12 + 23 i$ is in standard form.