Question

How do you simplify `(30sin^3xcosx)/(6cos^2xsinx)`?

Answer 1

`frac{30sin^3xcosx}{6cos^2sinx}`

`=(30)/(6)times(sin^3x)/(sinx)times(cosx)/(cos^2x)`

`=5timessin^2xtimes(1)/(cosx)`

`=(5sin^2x)/(cosx)`