How do you simplify #(30x^3y^4)/(6x^9y^-4)#?

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Answer 1 · 2016-08-16T04:03:16

#( 5 y^8)/x^6#
Answers should be given without negative or zero indices.

To simplify divide out common factors.

30 = # 5 xx 6#
6 = # 1 xx 6#

#6/6# = 1 leaving 5 as a factor in the numerator

# x^3# = # x xx x xx x#

# x^9# = # x xx x xx x xx x xx x xx x xx x xx x xx x#

#( x xx x xx x) /( x xx x xx x xx x xx x xx x xx x xx x xx x)#

#( x xx x xx x )/ (x xx x xx x)# = 1 This leaves

# 1/ (x xx x xx x xx x xx x xx x) = 1/x^6#

#y^4# = # (y xx y xx y xx y )#

# y^-4# = #1/ ( y xx y xx y xx y )#

#( y xx y xx y xx y)/1 / 1 / ( y xx y xx y xx y) #

multiply both factions by # ( y xx y xx y xx y )

This gives # y^8#