Question

How do you simplify `(3i)/(1+i) + 2/(2+3i)`?

Answer 1

`(-7 +12i)/( -1 + 5i)`

Explanation:

Use a common denominator:

`( 3i(2+3i) + 2(1+i))/((1+i)(2+3i))`

`(6i +9(i)^2 +2 +2i)/(2 + 3i +2i + 3(i)^2`

But `(i)^2 = -1` giving:

`(-7 +8i)/( -1 + 5i)`