How do you simplify #(3i)/(9-6i)#?
1 Answer
Dec 31, 2015
Explanation:
Divide each term by
#=>i/(3-2i)#
Now, to remove the imaginary part from the denominator and write the answer as a complex number in the form
#=>i/(3-2i)((3+2i)/(3+2i))#
Distribute. Notice that the bottom will form a difference of squares.
#=>(3i+2i^2)/(9-4i^2)#
To continue simplifying, rewrite
#=>(3i+2(-1))/(9-4(-1))=(-2+3i)/13#
Split apart the numerator to write in
#=>-2/13+3/13i#