How do you simplify #(3sqrt(18))/sqrt(48) - (2sqrt(6))/sqrt(80)#?

1 Answer
Jun 10, 2015

Answer:

#(9sqrt2)/(4sqrt3)-(2sqrt6)/(4sqrt5)#

Explanation:

Okay this might be wrong as I have only briefly touched this topic but this is what I would do:
#(3sqrt(9xx2))/sqrt(16xx3)-(2sqrt6)/sqrt(16xx5)# Which equals
#(9sqrt2)/(4sqrt3)-(2sqrt6)/(4sqrt5)#
I hope this is right, I'm sure someone will correct me if I'm wrong.