How do you simplify (3x^2+14x+8)/ (2x^2+7x-4) * (2x^2+9x-5)/(3x^2+16x+5)?

1 Answer
Jul 16, 2015

(3x+2)/(3x+1)

Explanation:

Factor the terms:

(3x^2+14x+8)/(2x^2+7x-4)*(2x^2+9x-5)/(3x^2+16x+5)=

((3x+2)(x+4))/((2x-1)(x+4))*((2x-1)(x+5))/((3x+1)(x+5))

Cancel the identical terms found in the factorisation:

((3x+2)(x+4))/((2x-1)(x+4))*((2x-1)(x+5))/((3x+1)(x+5))=

(3x+2)/(3x+1)