Question

How do you simplify `(3x^2 - 6x)/ (2x + 1) * (4x + 2 )/( x - 2)`?

Answer 1

`6x`

Explanation:

`(3x^2-6x)/(2x+1)*(4x+2)/(x-2)=>` Factor all possible terms:

`=[3x(x-2)]/(2x+1)*[2(2x+1)]/(x-2)=>`Cancel common terms:

`=[3x(cancel(x-2))]/(2x+1)*[2(2x+1)]/(cancel(x-2))=>` Also:

`=(3x)/cancel(2x+1)*[2(cancel(2x+1))]/1=>` You get:

`=6x`