How do you simplify #(3y^2z)/(15y^5)#?

1 Answer
EZ as pi
Jun 9, 2016

# z/(3y^3)#

Explanation:

Simplify the numbers first by dividing both by 3.

Subtract the indices of y. The bigger index is in the denominator, so the y's will be left there.

#(3y^2z)/(15y^5) = (cancel3y^2z)/(cancel15^5y^5)#

=# z/(3y^3)#

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