How do you simplify #(3z ^ { 4} ) ^ { 2} \cdot ( 2y ^ { 3} ) ^ { 3}#?

1 Answer
Shantelle
Oct 14, 2017

#72y^9z^8#

Explanation:

#(3z^4)^2*(2y^3)^3#

#9z^8*8y^9#
(The exponent #2# in #(3z^4)^2# applies to everything inside the parenthesis. This means #3^2*(z^4)^2#, which equals #9*z^8#. When you have a exponent to an exponent, that means you have to multiply them together. If you apply this concept to #(2y^3)^3# too, then you will get #8y^9#).

#72z^8*y^9# (multiply the 9 with the 8)

#72y^9z^8# (write in alphabetical order)

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