Question

How do you simplify `(4+3i)(7+i)`?

Answer 1

`25(1+i)`

Explanation:

Multiply out the brackets as normal but remembering that `i^2=-1`

Given:`" "(4+3i)(7+i)`

`28+4i+21i+3i^2`

`28+25i+3(-1)`

`25+25i`

`25(1+i)`