# How do you simplify #(4+ 3i) div (2 - i)#?

##### 1 Answer

Jul 13, 2016

#### Answer:

#### Explanation:

The *complex conjugate* of a complex number

#=(8+6i+4i-3)/(4+2i-2i+1)#

#=(5+10i)/5#

#=1+2i#

Jul 13, 2016

The *complex conjugate* of a complex number

#=(8+6i+4i-3)/(4+2i-2i+1)#

#=(5+10i)/5#

#=1+2i#