# How do you simplify  (-4 - 6i) + (-2 - 3i)  and write in a+bi form?

Nov 21, 2015

$- 6 - 9 i$

#### Explanation:

Treat the imaginary $i$ just like you would an $x$.

$\left(- 4 - 6 i\right) + \left(- 2 - 3 i\right)$

$- 4 - 6 i - 2 - 3 i$

$- 4 - 2 - 6 i - 3 i$

$\left(- 4 - 2\right) + \left(- 6 i - 3 i\right)$

$- 6 - 9 i$

Notice that this is in $a + b i$ form: the term without the $i$ comes first.