Question

How do you simplify `4/(7-9i)`?

Answer 1

`=14/65+i18/65`

Explanation:

Multiply numerator and denominator by the conjugate of the denominator `7+9i`
So the expressiion `=(4(7+9i))/((7-9i)(7+9i))=(28+36i)/(49+81)=28/130+(36i)/130=14/65+(18i)/65`
as `i^2=-1`