How do you simplify #4(fg+3g)+5g#?

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Answer 1 · 2018-03-25T19:30:05

#=>(4f+17)g#

We start with:

#=>4(fg+3g)+5g#

We distribute the #4#.

#=>4fg +12g+5g#

Now we can combine the terms containing only #g#.

#=>4fg+17g#

We can factor out a #g# from both terms.

#=>(4f+17)g#