Question

How do you simplify `(4 times 10^13)^-2`?

Answer 1

`(1/16)(1/10^-26)=(6.25*10^-28)`

Explanation:

`(a^1*b^x)^n=a^(1n)*b^(xn)`

The numbers in the parentheses both have their exponents multiplied by the exponent outside the parentheses.

In this case `4` is raised to the power of one, so it becomes `4^-2`, or `1/16`.
`10` is raised to the power of `13`, so it becomes `10^[13 * (-2)]` or `10^-26`