How do you simplify #(4 times 10^13)^-2#?

1 Answer

Answer:

#(1/16)(1/10^-26)=(6.25*10^-28)#

Explanation:

#(a^1*b^x)^n=a^(1n)*b^(xn)#

The numbers in the parentheses both have their exponents multiplied by the exponent outside the parentheses.

In this case #4# is raised to the power of one, so it becomes #4^-2#, or #1/16#.
#10# is raised to the power of #13#, so it becomes #10^[13 * (-2)]# or #10^-26#