How do you simplify #4 times sqrt 3 div sqrt2#?

2 Answers
Jun 12, 2018

Answer:

#(4sqrt3)/sqrt2#

Explanation:

Given: #4xxsqrt3-:sqrt2#.

#=4sqrt3-:sqrt2#

#=(4sqrt3)/sqrt2#

Jun 12, 2018

Answer:

#2sqrt6#

Explanation:

#(4sqrt3)/sqrt2#

#"to simplify multiply numerator/denominator by "sqrt2#

#•color(white)(x)sqrtaxxsqrtb=sqrt(ab)#

#["note "sqrtaxxsqrta=a]#

#=(4sqrt3)/sqrt2xxsqrt2/sqrt2#

#=(4sqrt6)/2=2sqrt6#