How do you simplify #4{z-6(r-5)+8[z-2r+3(r-1)]}#?

Question

1378 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-02-20T19:48:30

#= 36z+8r+24#

This is all one long term, but there are 2 terms in the brackets.
Start by simplifying the innermost brackets.

#4{z-6(color(red)(r-5))+8[z-2r+3color(blue)((r-1))]}#

They are unlike terms, so use the distributive law .

#=4{z color(red)(-6r+30)+8[z-2rcolor(blue)(+3r-3)]}" "larr# simplify

#=4{z -6r+30color(forestgreen)(+8[z+r-3])}#

#=4{z -6r+30color(forestgreen)(+8z+8r-24)}" "larr# simplify

#=4{9z+2r+6}" "larr xx 4#

#= 36z+8r+24#