Question

How do you simplify `(4cos^3x)/(sin^2x)*(sinx/(4cosx))^2`?

Answer 1

`=cosx/4`

Explanation:

`(4cos^3x)/sin^2x*(sinx/(4cosx))^2`

`=(4cos^3x)/sin^2x*(sin^2x/(16cos^2x))`

`=cosx/4`