# How do you simplify 4div( sqrt3 + sqrt2)?

I found: $4 \left(\sqrt{3} - \sqrt{2}\right)$
I think you can Rationalize (to get rid of roots in the denominator) multiplying and dividing by $\sqrt{3} - \sqrt{2}$ and get:
$\frac{4}{\sqrt{3} + \sqrt{2}} \cdot \frac{\sqrt{3} - \sqrt{2}}{\sqrt{3} - \sqrt{2}} = 4 \frac{\sqrt{3} - \sqrt{2}}{3 - 2} =$
$= 4 \left(\sqrt{3} - \sqrt{2}\right)$