How do you simplify #-4sqrt10+6sqrt40#?

1 Answer
Alan P.
Jul 8, 2015

#-4sqrt(10)+6sqrt(4) = 8sqrt(10)#

Explanation:

#sqrt(40) = sqrt(4)*sqrt(10) = 2sqrt(10)#
So
#6sqrt(40) = 6*2sqrt(10) = 12 sqrt(10)#

and
#-4sqrt(10)+6sqrt(10)#

#color(white)("XXXX")##=-4sqrt(10)+12sqrt(10)#

#color(white)("XXXX")##=(-4+12)(sqrt(10))#

#color(white)("XXXX")##=8sqrt(10)#

Related questions
See all questions in Addition and Subtraction of Radicals
Impact of this question
1454 views around the world
You can reuse this answer
Creative Commons License