How do you simplify #4sqrt5(3sqrt5+8sqrt2)#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Barney V. Mar 21, 2017 #92sqrt2sqrt5# Explanation: #4sqrt5(3sqrt5+8sqrt2)# #:.=4sqrt5 xx 3sqrt5+4sqrt5 xx 8sqrt2# #:.=sqrt5 xx sqrt5=5# #:.=(12 xx 5)+32 xx sqrt5 xx sqrt2# #:.=60+32 xx sqrt5 xx sqrt2# #:.=92sqrt2sqrt5# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 886 views around the world You can reuse this answer Creative Commons License