How do you simplify # (4sqrt7-8sqrt3)(5sqrt7+10sqrt3)#?
1 Answer
May 4, 2016
Explanation:
Expand the brackets using FOIL or multiply each term in the 2nd bracket by each term in the 1st.
#4sqrt7(5sqrt7+10sqrt3)-8sqrt3(5sqrt7+10sqrt3)# Noting that :
#sqrtaxxsqrta=a# and from the question here
#sqrt7xxsqrt7=7# distribute 1st bracket
#rArr(4sqrt7xx5sqrt7)+(4sqrt7xx10sqrt3)=140+40sqrt21#
#[" using " sqrtaxxsqrtbhArrsqrtab]"so"sqrt7xxsqrt3=sqrt21# distribute 2nd bracket
#rArr(-8sqrt3xx5sqrt7)+(-8sqrt3xx10sqrt3)#
#=-40sqrt21-240# Combining the 2 expansions
#140+40sqrt21-40sqrt21-240# [Note :
#40sqrt21-40sqrt21=0]#
#rArr(4sqrt7-8sqrt3)(5sqrt7+10sqrt3)=140-240=-100#