How do you simplify #4x ^ { 4} y ^ { 7} \sqrt { 2y } - 2x ^ { 4} y ^ { 7} \sqrt { 2y } + 4x ^ { 4} y ^ { 6} \sqrt { 2y }#?

1 Answer
sankarankalyanam
Oct 19, 2017

Taking out common terms #2x^4y^6sqrt(2y)# outside, we get

#=2^(3/2)*x^4*y^(13/2)*(y+2)#

Explanation:

Taking out common terms #2x^4y^6sqrt(2y)# outside, we get
#2x4t^6sqrt(2y)(2y-y+2)#
#=2x^4y^6sqrt(2y)(y+2)#
#= 2sqrt2*x^4*y^(6+(1/2))(y+2)#
#=2^(3/2)*x^4*y^(13/2)*(y+2)#

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