How do you simplify (4xy^3)/(x^2y)*y/(8x)?

May 12, 2018

Multiply and divide out common factors

Explanation:

$\frac{4 x {y}^{3}}{{x}^{2} y} \times \frac{y}{8 x} = \frac{4 x {y}^{4}}{8 {x}^{3} {y}^{1}}$

The common factors are 4xy Divide both the numerator and the denominator by the the common factors of 4xy

$\frac{4 x {y}^{4}}{4 x y} = {y}^{3}$

$\frac{8 {x}^{3} {y}^{1}}{4 x y} = 2 {x}^{2}$

So the simplified version of the fraction is

${y}^{3} / \left(2 {x}^{2}\right)$