How do you simplify #(5+sqrt3)(5-sqrt3)#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer George C. Jun 5, 2015 This is of the form #(a+b)(a-b)# with #a=5# and #b=sqrt(3)# #(a+b)(a-b) = a^2-b^2# So #(5+sqrt(3))(5-sqrt(3)) = 5^2-(sqrt(3))^2 = 25 - 3 = 22# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 1345 views around the world You can reuse this answer Creative Commons License