How do you simplify #5/sqrt5#?

2 Answers
Apr 12, 2017

Answer:

#sqrt(5)#

Explanation:

Whenever you have a surd as the denominator, we rationalise it, meaning we multiply it and the numerator (because multiplying any number by 1 doesn't change it) by itself to get a 'normal' number on the bottom. So in this case we would do

#5/sqrt(5) xx sqrt(5)/sqrt(5) = (5sqrt(5))/5#

*notice how #sqrt(5)/sqrt(5)=1# so by multiplying #5/sqrt(5)# we are to changing it *

Then we would simplify #(5sqrt(5))/5# to get #(1sqrt(5))/1# which equals to #sqrt(5)#

Apr 13, 2017

Answer:

#sqrt5#

Explanation:

#color(blue)(5/sqrt(5)#

We need to simplify this.The first thing we need to know is that, we need to rationalize the denominator.

So, multiply the denominator and numerator with #sqrt5#

#rarr5/sqrt5*sqrt5/sqrt5#

#rarr(5sqrt5)/5#

#rarr(cancel5sqrt5)/cancel5#

#color(green)(rArrsqrt5#

Hope this helps... :)