How do you simplify #(5)/(z+2) - (3)/(z+3)#?

1 Answer
ceenik
Apr 24, 2017

#(2z+9)/[(z+2)(z+3)]#

Explanation:

Start by creating common denominators.
So,

#5/(z+2)##((z+3)/(z+3))# #-# #3/(z+3)##((z+2)/(z+2))#

#(5z+15)/[(z+2)(z+3)]# #-# #(3z+6)/[(z+2)(z+3)]#

Subtract the numerators now that we have the same denominator on both fractions.

#(2z+9)/[(z+2)(z+3)]#

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