How do you simplify #5sqrt6(sqrt3 - 2sqrt7)#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer P dilip_k May 5, 2016 #15sqrt2-10sqrt42# Explanation: #5sqrt6(sqrt3-2sqrt7)# #=>5sqrt6*sqrt3-10sqrt6*sqrt7# #=>5sqrt(9*2)-10sqrt42# #=>15sqrt2-10sqrt42# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 1204 views around the world You can reuse this answer Creative Commons License