How do you simplify #6(3-2z) + 11z - 4#?

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Answer 1 · 2017-01-08T14:29:49

See full simplification process below in the explanation

First we expand the term in parenthesis:

#color(red)(6)(3 - 2x) + 11z - 4 ->#

#(color(red)(6) xx 3) - (color(red)(6) xx 2z) + 11z - 4 ->#

#18 - 12z + 11z - 4#

Now, we can group and then combine line terms:

#18 - 4 - 12z + 11z ->#

#14 + (-12 + 11)z ->#

#14 + (-1z) ->#

#14 - z#