# How do you simplify 6/(3-3i)?

Jun 19, 2018

I would multiply and divide by the Complex Conjugate $3 + 3 i$:
$\frac{6}{3 - 3 i} \cdot \frac{3 + 3 i}{3 + 3 i} = \frac{18 + 18 i}{9 + 9} = \frac{18}{18} + \frac{18}{18} i = 1 + i$
remembering that: ${i}^{2} = - 1$