# How do you simplify (6e^(4x))/(8e)?

Dec 27, 2016

$\frac{3}{4} {e}^{4 x - 1}$
Using the $\textcolor{b l u e}{\text{law of exponents}}$
$\textcolor{\mathmr{and} a n \ge}{\text{Reminder }} \textcolor{red}{\overline{\underline{| \textcolor{w h i t e}{\frac{2}{2}} \textcolor{b l a c k}{\frac{{a}^{m}}{{a}^{n}} = {a}^{m - n}} \textcolor{w h i t e}{\frac{2}{2}} |}}}$
$\Rightarrow \frac{6 {e}^{4 x}}{8 {e}^{1}} = \frac{6}{8} \times {e}^{4 x} / {e}^{1} = \frac{3}{4} \times {e}^{4 x - 1} = \frac{3}{4} {e}^{4 x - 1}$