How do you simplify #(6x+6)/7 -: (4x+4)/(x-2)#?
1 Answer
Feb 14, 2016
# (3x - 6)/14#
Explanation:
first step is to factor both numerators
#( 6(x +1))/7 ÷ (4(x +1))/(x-2)#
when dividing 2 fractions , we can change to multiplying , by 'inverting' the 2nd fraction ( turn it upside down ).hence becomes:
#(6(x+1))/7 xx (x-2)/(4(x+1)# simplifying :
#(6cancel(x+1))/7 xx (x-2)/(4cancel(x+1))#
# = (6(x-2))/28 =( 3(x-2))/14 = (3x-6)/14 #
