How do you simplify #7^ { 12} \div 7^ { 4} #?

2 Answers
sankarankalyanam
Oct 5, 2017

#7^8#

Explanation:

#7^12/7^4=7^12*7^-4=7^(12-4)=7^8#

Aliter :
#7^12/7^4=((7*7*7*7*7*7*7*7*color(red)(cancel(7*7*7*7)))/color(red)cancel(7*7*7*7))#
#=7*7*7*7*7*7*7*7=7^8#

Jim G.
Oct 5, 2017

#5764801#

Explanation:

#rArr(cancel(7)xxcancel(7)xxcancel(7)xxcancel(7)xx7xx7xx7xx7xx7xx7xx7xx7)/(cancel(7)xxcancel(7)xxcancel(7)xxcancel(7))#

#=7xx7xx7xx7xx7xx7xx7xx7#

#=7^8#

#=5764801#

#"this calculation can be simplified using the following rule"#

#•color(white)(x)a^m-:a^n=a^m/a^n=a^((m-n))#

#rArr7^(12)-:7^4=7^(12)/7^4=7^((12-4))=7^8#

Related questions
Impact of this question
794 views around the world
You can reuse this answer
Creative Commons License