How do you simplify #(7+7i)/(2)#? Precalculus Complex Numbers in Trigonometric Form Division of Complex Numbers 1 Answer GiĆ³ Jan 5, 2016 I got #3.5+3.5i#. Explanation: I would write it as: #7/2+7/2i=3.5+3.5i# In the #a+bi# form. Answer link Related questions How do I graphically divide complex numbers? How do I divide complex numbers in standard form? How do I find the quotient of two complex numbers in polar form? How do I find the quotient #(-5+i)/(-7+i)#? How do I find the quotient of two complex numbers in standard form? What is the complex conjugate of a complex number? How do I find the complex conjugate of #12/(5i)#? How do I rationalize the denominator of a complex quotient? How do I divide #6(cos^circ 60+i\ sin60^circ)# by #3(cos^circ 90+i\ sin90^circ)#? How do you write #(-2i) / (4-2i)# in the "a+bi" form? See all questions in Division of Complex Numbers Impact of this question 1587 views around the world You can reuse this answer Creative Commons License