Question

How do you simplify `7^ (log_7 9 - log_7 8)`?

Answer 1

`7^(log_7 9-log_7 8)=9/8`

Explanation:

`7^(log_7 9-log_7 8)`

`=7^(log_7 (9/8)`-> use property `log_b(x/y)=log_bx-log_by` for the exponent

`=9/8`->use inverse property `b^(log_bx)=x`