How do you simplify $7 \sqrt{x} + 3 \sqrt{y} - \sqrt{x} - 3 \sqrt{y}$ $7sqrtx+3sqrty-sqrtx-3sqrty$ ?

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Answer 1 · 2018-05-16T05:58:08

$6 \sqrt{x}$ $6\sqrt{x}$

The $3 \sqrt{y} - 3 \sqrt{y}$ $3\sqrt{y}-3\sqrt{y}$ cancel each other out.

This leaves you: $7 \sqrt{x} - \sqrt{x}$ $7\sqrt{x}-\sqrt{x}$

Since they have the same variables, they can be treated as normal algebra, which gives you $6 \sqrt{x}$ $6\sqrt{x}$

Answer 2 · 2018-05-16T05:59:11

$6 \sqrt{x}$ $6sqrtx$

Add the like terms first and then simplify further.

$7 \sqrt{x} + 3 \sqrt{y} - \sqrt{x} - 3 \sqrt{y}$ $7sqrtx + 3sqrty - sqrtx - 3sqrty$

$7 \sqrt{x} - \sqrt{x} + 3 \sqrt{y} - 3 \sqrt{y}$ $7sqrtx-sqrtx+3sqrty-3sqrty$

$7sqrtx-sqrtx+cancel(3sqrty-3sqrty)$

$7sqrtx-sqrtx$

$6sqrtx$

Another way to arrive to $6sqrtx$ is:

$7sqrtx-sqrtx$

$sqrtx(7 - 1)$

$sqrtx xx 6$

$6sqrtx$

How do you simplify 7sqrtx+3sqrty-sqrtx-3sqrty7√x+3√y−√x−3√y7sqrtx+3sqrty-sqrtx-3sqrty?