How do you simplify #(-7x^4y^2)(-2x^2y^2)#?

1 Answer
Mar 31, 2015

You can divide the calculation in three steps:

  1. Firts of all, the sign: when multiplying two numbers, look at the sign of the factors. Same sign (which means #+ * +# or #- * -#) gives a positive result, while the other cases (i.e. #+ * -# or #- * +#) gives a negative result. Since you have the multiplication of two negative numbers, the result will be positive.
  2. The numeric part: this is probably the easiest part: you simply need to multiply the two numbers. So, you have #7*2=14#
  3. Variables: When multiplying two variables, simply add the exponent: so #x^4*x^2 = x^{4+2} = x^6#, and #y^2 * y^2 = y^{2+2}=y^4#.

After all, writing a power is just a short way for writing a product of several factors, all equal to each other. So, writing the expression in a more complicated fashion, you would have
#(-7x^4y^2)(-2x^2y^2) =#
#(-7)(-2)x*x*x*x*y*y*x*x*y*y#
Now, #(-7)(-2)# is #14# for what we said on points 1 and 2 above. Then, simply rearrange the variable and count them!
#(-7)(-2)x*x*x*x*y*y*x*x*y*y=#
#14*x*x*x*x*x*x*y*y*y*y=14x^6y^4#