How do you simplify #8^(4/3)#?

2 Answers
Jan 29, 2016

#16#

Explanation:

There is an intuitive approach to problems like this.

When an exponent is in the form #a/b#, I do the following in my head:

What is the number to the #1/b# root?

In this case, I'd ask, what is #8# to the #1/3# root? This can also be interpreted as, what is the cube root of #8#?

I know that #2^3=8#, so the cube root of #8# is #2#.

The next step is taking #2# to the #a# power, and here #a=4#.

#2^4=16#, so #8^(4/3)=16#.

Apr 14, 2018

#16#

Explanation:

The more formal way to approach this problem is to use the rule #(a^b)^c=a^(bc)# and to rewrite #8# in its prime factorization.

The "simplest" form of #8# is given by #8=2*2*2=2^3#.

Then,

#8^(4/3)=(2^3)^(4/3)=2^(3*4/3)=2^4=16#