Question

How do you simplify `(8^ { 6} ) ^ { 2} \div ( 8^ { 2} ) ^ { 5}`?

Answer 1

64

Explanation:

`(a^m)^n=a^(mn)`

Hence
`(8^6)^2/(8^2)^5=8^(6xx2)/(8^(2xx5))=8^12/8^10`

`1/a^m=a^-m` and `a^mxxa^n=a^(m+n)`

`(8^6)^2/(8^2)^5=8^12xx8^-10=8^(12-10)=8^2=64`