How do you simplify # (8 - b)(-3) + 6b + 12 - 10b#?

2 Answers
Apr 11, 2018

Answer:

They wrote this really weird but I guess that's math people for ya. I got #-12-b# explanation below.

Explanation:

So the first step is to distribute the #-3# to the #(8-b)# and don't forget that a negative times a negative equals a positive so #-3 * -b=3b#
Once you do that you should get #-24+3b+6b +12-10b#
After you solve for that it's basic combining of like terms: #-12+9b-10b#
And finally you get #-12-b#

Apr 11, 2018

Answer:

#-b-12#

Explanation:

First, multiply out the #(8−b)(−3)# term like this: #-3*8+(-3)*-b#, which results in #-24+3b#

The whole expression becomes: #-24+3b+6b+12-10b#.

Then combine like terms (add all the b's together and add all the constants together): #(3+6-10)b+(-24+12)#, which equals #-b-12#.