# How do you simplify  (8 - b)(-3) + 6b + 12 - 10b?

Apr 11, 2018

They wrote this really weird but I guess that's math people for ya. I got $- 12 - b$ explanation below.

#### Explanation:

So the first step is to distribute the $- 3$ to the $\left(8 - b\right)$ and don't forget that a negative times a negative equals a positive so $- 3 \cdot - b = 3 b$
Once you do that you should get $- 24 + 3 b + 6 b + 12 - 10 b$
After you solve for that it's basic combining of like terms: $- 12 + 9 b - 10 b$
And finally you get $- 12 - b$

Apr 11, 2018

$- b - 12$
First, multiply out the (8−b)(−3) term like this: $- 3 \cdot 8 + \left(- 3\right) \cdot - b$, which results in $- 24 + 3 b$
The whole expression becomes: $- 24 + 3 b + 6 b + 12 - 10 b$.
Then combine like terms (add all the b's together and add all the constants together): $\left(3 + 6 - 10\right) b + \left(- 24 + 12\right)$, which equals $- b - 12$.