# How do you simplify #(8 i)/(2-i)#?

##### 1 Answer

May 20, 2016

#### Answer:

#### Explanation:

Given a complex number *complex conjugate* of that number is

In this case, we will use that property, along with the fact that the conjugate of

#=(-8+16i)/5#

#=-8/5+16/5i#