How do you simplify #8/(m^2) * (m^2/(2c))^2#?

1 Answer
Jul 25, 2015

Answer:

Cancel the terms common to the numerator and to the denominator.

Explanation:

Your initial expression looks like this

#8/m^2 * (m^2/(2c))^2#

Notice that you have #m^2# as the denominator of the first fraction and #(m^2)^2# as the numerator of the second fraction. This means that you can write

#8/m^2 * (m^2)^2/((2c)^2) = 8/m^2 * (m^2 * m^2)/(2^2 * c^2) = (cancel(4) * 2)/cancel(m^2) * (cancel(m^2) * m^2)/(cancel(4) * c^2)#

Your initial expression will thus be equivalent to

#8/m^2 * (m^2/(2c))^2 = color(green)((2 * m^2)/c)#