How do you simplify #(-8-sqrt512)/4#?
1 Answer
Jun 16, 2018
Explanation:
#"simplify "sqrt512" using prime factors"#
#sqrt512=sqrt(2^9)=sqrt(2^4xx2^4xx2)#
#color(white)(xxxxxx)=sqrt(16xx16xx2)=4xx4xxsqrt2=16sqrt2#
#(-8-16sqrt2)/4=(-8)/4-(16sqrt2)/4=-2-4sqrt2#
