How do you simplify #(8x+16) / (x^2-1 )*( x+1)/(4x+8)#?

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Answer 1 · 2015-09-21T00:22:33

The answer is #2/(x-1)#.

#(8x+16)/(x^2-1) * (x+1)/(4x+8)#

Factor out #2# from #(8x+16)#.

#(2(4x+8))/(x^2-1) * (x+1)/(4x+8)#

Cancel #(4x+8)# in the numerator and denominator.

#(2cancel(4x+8))/(x^2-1) * (x+1)/cancel(4x+8)=#

#2/(x^2-1) * (x+1)/1#

Factor #x^2-1#.

#2/((x+1)(x-1)) * (x+1)/1#

Cancel #x+1# in the numerator and denominator.

#2/(cancel(x+1)(x-1)) * cancel(x+1)/1=#

#2/(x-1)#