How do you simplify #(9-4i)/i#?

1 Answer
Jul 27, 2016

Answer:

#-4-9i#

Explanation:

To eliminate the i from the denominator of the fraction multiply numerator and denominator by i . This will leave a real number on the denominator.

#color(orange)"Reminder" color(red)(|bar(ul(color(white)(a/a)color(black)(i^2=(sqrt(-1))^2=-1)color(white)(a/a)|)))#

#rArr(9-4i)/i xxi/i=(i(9-4i))/i^2=(9i-4i^2)/i^2=(4+9i)/(-1)#

#rArr(9-4i)/i=-4-9i#