How do you simplify #(-9-sqrt108) / 3#?
By reducing the radical and dividing by three.
In the problem, you have
If you look up how to do it there will be a multitude of examples for you to look at, but it's really hard to format it here.
108 = 542 = 2722 = 9322 = 33322. We can take out a pair of two's and three's which gives us our simplified radial
That simplified radical gives us the problem
Now we can factor out three's from